(Filed on behalf of Bentley user)
Bentley RailTrack 08.11.07.564
User has placed a CV10.75 and DV10.75 turnout into straight track which has a bearing of 90 degrees. The results should be the same difference in angle at .2 & .3 for each turnout.
In the UK we use 'centre line measure' to define crossing angles, to calculate the angle in degrees you must use the following:
2*(Atan(0.5/N)) where N is the crossing angle eg 10.75.
For a 10.75 this equates to 5^ 19' 33.61", so when a right hand leading turnout is placed into a straight of bearing 90^ the resultant crossing angle should be 95^ 19' 33.61".
CV10.75 Output (CORRECT)
Station Easting Northing Direction Radius Point
100.000 65424.753 43265.596 90^00'00.00" 286.5354 .1
0.000 65435.558 43265.596 90^00'00.00" 0.0000 .0
126.199 65450.952 43265.596 90^00'00.00" 0.0000 .2
0.000 65450.885 43264.168 95^19'33.61" 0.0000 .3
DV10.75 Output (WRONG)
Station Easting Northing Direction Radius Point
200.000 65524.753 43265.596 90^00'00.00" 366.3223 .1
0.000 65538.423 43265.596 90^00'00.00" 0.0000 .0
229.174 65553.927 43265.596 90^00'00.00" 0.0000 .2
0.000 65553.861 43264.168 95^17'17.77" 0.0000 .3
This is off by 0^ 2' 15.84", which in design terms is very significant.
FYI - I have used the 'Switch & Crossings-113A.txt library.
Bentley Support has been unable to reproduce the issue.